Accenture Software Engineering Practice Question
Choose the correct pseudocode for the below problem statement. Problem Statement : Find Maximum value Choose a pseudo code to find the maximum values in each row of a matrix. Assume it is a 3x3 matrix. Explanation : Matrix will be with index (0,0) (0,1) (0,2) (1,0) (1,1) (1,2) (2,0) (2,1) (2,2) Assume the values for this matrix are 12 23 18 45 32 60 42 39 23 The output will be Max value in row 1 is 23 Max value in row 2 is 60 Max value in row 3 is 42 a. BEGIN DECLARE variable arr[3][3] FOR i IN 0 to 2 DO FOR j IN 0 to 2 DO READ arr[i][j] END FOR END FOR SET max = arr[i][0] FOR i IN 0 TO 2 DO FOR j IN 0 TO 2 DO IF arr[i][j]>max THEN max = arr[i][j] END IF END FOR PRINT "Max value in row "+(i+1)+" is "+max END FOR END b. BEGIN DECLARE variable arr[3][3] FOR i IN 0 to 2 DO FOR j IN 0 to 2 DO END FOR END FOR FOR i IN 0 TO 2 DO READ arr[i][j] SET max = arr[i][0] FOR j IN 0 TO 2 DO IF arr[i][j]>max THEN max = arr[i][j] END IF END FOR PRINT "Max value in row "+(i+1)+" is "+max END FOR END c. BEGIN DECLARE variable arr[3][3] FOR i IN 0 to 2 DO FOR j IN 0 to 2 DO READ arr[i][j] END FOR END FOR FOR i IN 0 TO 2 DO SET max = arr[i][0] FOR j IN 0 TO 2 DO IF arr[i][j]>max THEN max = arr[i][j] END IF END FOR PRINT "Max value in row "+(i+1)+" is "+max END FOR END d. BEGIN DECLARE variable arr[3][3] FOR i IN 0 to 2 DO FOR j IN 0 to 2 DO READ arr[i][j] END FOR END FOR FOR i IN 0 TO 2 DO SET max = arr[i][0] FOR j IN 0 TO 2 DO IF arr[i][j]>max THEN max = arr[i][j] END IF END FOR END FOR PRINT "Max value in row "+(i+1)+" is "+max ENDAnswer options
A
BEGIN DECLARE variable arr[3][3] FOR i IN 0 to 2 DO FOR j IN 0 to 2 DO READ arr[i][j] END FOR END FOR SET max = arr[i][0] FOR i IN 0 TO 2 DO FOR j IN 0 TO 2 DO IF arr[i][j]>max THEN max = arr[i][j] END IF END FOR PRINT "Max value in row "+(i+1)+" is "+max END FOR END
B
BEGIN DECLARE variable arr[3][3] FOR i IN 0 to 2 DO FOR j IN 0 to 2 DO END FOR END FOR FOR i IN 0 TO 2 DO READ arr[i][j] SET max = arr[i][0] FOR j IN 0 TO 2 DO IF arr[i][j]>max THEN max = arr[i][j] END IF END FOR PRINT "Max value in row "+(i+1)+" is "+max END FOR END
C
BEGIN DECLARE variable arr[3][3] FOR i IN 0 to 2 DO FOR j IN 0 to 2 DO READ arr[i][j] END FOR END FOR FOR i IN 0 TO 2 DO SET max = arr[i][0] FOR j IN 0 TO 2 DO IF arr[i][j]>max THEN max = arr[i][j] END IF END FOR PRINT "Max value in row "+(i+1)+" is "+max END FOR END
D
BEGIN DECLARE variable arr[3][3] FOR i IN 0 to 2 DO FOR j IN 0 to 2 DO READ arr[i][j] END FOR END FOR FOR i IN 0 TO 2 DO SET max = arr[i][0] FOR j IN 0 TO 2 DO IF arr[i][j]>max THEN max = arr[i][j] END IF END FOR END FOR PRINT "Max value in row "+(i+1)+" is "+max END
Correct answer: BEGIN DECLARE variable arr[3][3] FOR i IN 0 to 2 DO FOR j IN 0 to 2 DO READ arr[i][j] END FOR END FOR FOR i IN 0 TO 2 DO SET max = arr[i][0] FOR j IN 0 TO 2 DO IF arr[i][j]>max THEN max = arr[i][j] END IF END FOR PRINT "Max value in row "+(i+1)+" is "+max END FOR END
Explanation
Correct answer: BEGIN DECLARE variable arr[3][3] FOR i IN 0 to 2 DO FOR j IN 0 to 2 DO READ arr[i][j] END FOR END FOR FOR i IN 0 TO 2 DO SET max = arr[i][0] FOR j IN 0 TO 2 DO IF arr[i][j]>max THEN max = arr[i][j] END IF END FOR PRINT "Max value in row "+(i+1)+" is "+max END FOR END.